Question 132012
logX + logX + 1 = log12 
2logX+1=log12
1=log12-2logx
1=log12-logx^2
{{{1=log(12/x^2) }}}

{{{1=log(10,12/x^2)}}}


By basic definition of logarithms:
{{{10^1= 12/x^2}}}
{{{10x^2 = 12}}}
{{{x^2=12/10=6/5}}}


Since x must be a positive number,
{{{x= sqrt(6/5)}}}
{{{x=sqrt(30)/5}}}


R^2