<PRE><B>Question 131994</B>
SOLUTION -
 Let the digit at once place be x
 and the digit at tens place be y
            Number=10y+x
  Reversing number=10x+y
 According to the condition we have
   x=4y    .....(i)
 According to the second condition we have
   10x+y=10y+x+54
   10x+y-10y-x=54
   9x-9y=54
   x-y=6           (dividing whole equation by 9)
  substituting the value of x from equation (i) we have
  4y-y=6
  3y=6
 {{{3y/3}}}={{{6/3}}}
  y=2
 substituting the value of y in equation (i) we have
  x=4y
  x=4*2
  x=8
 therefore 
     number is 10y+x=10*2+8=28
 
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