Question 131943
{{{h=16t^2+vt+s}}}


Swap the left and right sides of the equation:
{{{16t^2+vt+s=h}}}


Add -h to both sides:
{{{16t^2+vt+(s-h)=0}}}


Now you have a quadratic equation in t in standard form with coefficients, a = 16, b = v, and c = (s - h), so use the quadratic formula:


{{{t = (-v +- sqrt( v^2-4*16*(s-h) ))/(2*16) }}} 


{{{t = (-v +- sqrt( v^2-64(s-h) ))/32 }}}