Question 131904


{{{w^2+3w-54=0}}} Start with the given equation


{{{(w+9)(w-6)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{w+9=0}}} or  {{{w-6=0}}} 


{{{w=-9}}} or  {{{w=6}}}    Now solve for w in each case



So our answer is 

 {{{w=-9}}} or  {{{w=6}}} 



Notice if we graph {{{y=x^2+3x-54}}}  (just replace w with x)  we can see that the roots are {{{x=-9}}} and  {{{x=6}}} . So this visually verifies our answer.



{{{ graph(500,500,-10,10,-10,10,0, x^2+3x-54) }}}