Question 19955
Given the vertex (3,-2) passing through ( 2,-5) write in {{{ y=A(x-h)^2+k }}} form.

vertex is given by h,k  ......so h=3,k=-2
since it passes through 2,-5,this when substituted should give us value of A
{{{ y=A(x-h)^2+k }}} ={{{ y=A(x-3)^2-2 }}}
{{{ -5=A(2-3)^2-2 }}}
-5=A-2.....or.....A=-5+2=-3..hence eqn. is
{{{ y=(-3)*(x-3)^2-2 }}}