Question 131732
{{{n-n/3=1/2}}} is equivalent to:


{{{n/1-n/3=1/2}}}.


You need a lowest common denominator for the three fractions, and between denominators of 1, 2, and 3, all of which are either 1 or prime, the LCD is the product of the three, {{{1*2*3=6}}}, so:


{{{(6/6)(n/1)-(2/2)(n/3)=(3/3)(1/2)}}}, which is equivalent to your original equation because I multiplied each of the terms by 1.  {{{6/6=2/2=3/3=1}}}


{{{6n/6-2n/6=3/6}}}


Now multiply by 6:
{{{6n-2n=3}}}


{{{4n=3}}}


{{{n=3/4}}}


Check the answer:

{{{n-n/3=1/2}}}
{{{(3/4)-(3/4)/3=1/2}}}
{{{(3/4)-(3/4)(1/3)=1/2}}}
{{{(3/4)-(1/4)=2/4=1/2}}} Answer checks