Question 19925
Solve:
{{{sqrt(3x)+10 = 2x-5}}} Subtract 10 from both sides.
{{{sqrt(3x) = 2x-15}}} Square both sides of the equation.
{{{3x = 4x^2 - 60x + 225}}} Subtract 3x from both sides.
{{{4x^2 - 63x + 225 =0}}} Solve this quadratic equation using the quaratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}

{{{x = (-(-63)+-sqrt((-63)^2-4*4*225))/2(4)}}}
{{{x = (63+-sqrt(3969-3600))/8}}}
{{{x = (63+-sqrt(369))/8}}}
{{{x = (63+- 3sqrt(41))/8}}}
{{{x = 63/8 + (3/8)sqrt(41)}}} or {{{x = 63/8 - (3/8)sqrt(41)}}}