Question 131606
{{{sqrt((a + 5)^2)}}}
There is always a + and a - square root
For instance:
{{{sqrt(81) = 9}}}
and
{{{sqrt(81) = -9}}}
That's because {{{9*9 = 81}}} and {{{-9*-9 = 81}}}
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{{{sqrt((a + 5)^2) = a + 5}}}
and
{{{sqrt((a + 5)^2) = -a - 5}}}