Question 131646
Solve the following equations:

(a - 1) /( a^2 - 4) +  1 /(a - 2) = (a + 4) /(a + 2)
Multiply thru by (a^2-4) to get:
(a-1) + (a+2) = (a+4)(a-2)
2a+1 = a^2+2a-8
a^2=9
a=3 or a=-3
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(x^2+7x+12)/(2x+6)*(x/(x^2-16)
Factor where you can:
= [(x+3)(x+4)/2(x+3)]*[x/(x-4)(x+4)]
Cancel the (x+3) and the (x+4) factors to get:
= [1/2] * [x/(x-4)]
= x/[2(x-4)]
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Cheers,
Stan H.