Question 131613
To find the axis of symmetry, use this formula:


{{{x=-b/(2a)}}}


From the equation {{{y=-3x^2+2x-5}}} we can see that a=-3 and b=2


{{{x=(-2)/(2*-3)}}} Plug in b=2 and a=-3



{{{x=(-2)/-6}}} Multiply 2 and -3 to get -6




{{{x=1/3}}} Reduce



So the axis of symmetry is  {{{x=1/3}}}