Question 131565
Olivia, Newt, and John were each born 3 years apart, with Olivia the youngest and john the oldest. The sum of the squares of their ages is 606. How old is each?
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Let Olivia's age be "x"
Newt's age is "x+3"
John's age is "x+6"
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EQUATION
x^2 + (x+3)^2 + (x+6)^2 = 606
x^2 + x^+6x+9 + x^2+12x+36 = 606
3x^2 + 18x + 45 = 606
x^2 + 6x - 187 = -
(x-11)(x+17)=0
Positive Solution:
x = 11 (Olivia's age)
x+3 = 14 (Newt's age)
x+6 = 17 (John's age)
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Cheers,
Stan H.