<PRE><B>Question 131557</B>
Perfectly good start:


x = the NUMBER of student tickets
y = the NUMBER of GA tickets


And we know that {{{x+y=525}}}  (First equation)


Since student tickets cost $4, the total amount of money collected from the sale of student tickets must be 4 times the number of student tickets, i.e., 4x.


Likewise, the total money collected from general admission tickets must be 6y.


And since those were the only two types of tickets sold, these two expressions must add up to the total amount of money collected, or:


{{{4x+6y=2876}}} (Second equation)


Let&#39;s solve this by elimination.


Multiply the first equation by -4:
{{{-4x-4y=2100}}}


Now add this new equation term-by-term to the second equation:
{{{(-4x-4y)=-2100}}} + {{{4x+6y=2876}}} = {{{0x+2y=776}}}


{{{2y=776}}}
{{{y=388}}}


388 general admission tickets.


Go back to the original first equation and multiply by -6, then add term-by-term to the second equation:
{{{-6x-6y=-3150}}} + {{{4x+6y=2876}}} = {{{-2x+0y=-274}}}


{{{-2x=-274}}}
{{{x=137}}}


137 student tickets.


Check:
388 + 137 = 525


388 * 6 = 2328
137 * 4 = 548


2328 + 548 = 2876.  Answer checks.
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