Question 131486
3x^2=2x+5
so zero the equation by moving all the terms in one side 
3x^2-2x-5=0
factor this now
(AC method)= 5*3= 15
two number the prdouct of them will be 15 and the differece between them is 2 
which will be 3 and 5
now do the grouping
3x^2+3X-5x-5=0
3x(x+1)-5(x+1)=(x+1)(3x-5)=0
so now the two value that satisified the equation is x= -1 and 5/3