Question 131426
{{{ ((-9x^3)^2)*(-1/9)*x^6 }}}
If you have something that looks like {{{(a^b)^c}}}you just
multiply the exponents {{{(a^b)^c = a^(b*c)}}}. As a numerical
example: {{{(x^3)^4 = (x^3)*(x^3)*(x^3)*(x^3)}}} and
{{{(x^3)*(x^3)*(x^3)*(x^3) = (x*x*x)*(x*x*x)*(x*x*x)*(x*x*x)}}} so,
{{{(x^3)^4 = x^12}}}
{{{ ((-9x^3)^2)*(-1/9)*x^6 = ((-9)^2)*(x^6)*(x^6)*(-1/9)}}}
You should know that {{{(a^b)*(a^c) = a^(b+c)}}}
{{{((-9)^2)*(x^6)*(x^6)*(-1/9) = 81*(-1/9)*x^12}}}
{{{ 81*(-1/9)*x^12 = -9*(x^12)}}} answer