Question 131310
I think you meant:  {{{y^3(y^3-y)y}}}.  So if {{{y=3}}}, then your expression becomes:


{{{(3)^3((3)^3-3)3=27(27-3)3=27*24*3=1944}}}.  That is not one of the answers given, so I suspect you typed the problem incorrectly.


If it was actually supposed to be {{{y^3(y^3-y)}}} (since putting that extra factor of y at the end would have been silly and should have been written {{{y^4(y^3-y)}}}),  Then you have:


{{{(3)^3((3)^3-3)=27(27-3)=27*24=648}}}, answer D.