Question 131224
{{{6x^2+7x=3}}} Start with the given equation



{{{6x^2+7x-3=0}}}  Subtract 3 from both sides. 




{{{(2x+3)(3x-1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{2x+3=0}}} or  {{{3x-1=0}}} 


{{{x=-3/2}}} or  {{{x=1/3}}}    Now solve for x in each case



So our solutions are 


 {{{x=-3/2}}} or  {{{x=1/3}}}