Question 19718
roots of the equation: 4 +- sqrt(7)
sum of the roots: (4+sqrt(7))+(4-sqrt(7)) = 4+4= 8
product of the roots: (4+sqrt(7))*(4-sqrt(7)) = (16-7)= 9
<P>
in a quadratic equation of form
{{{ax^2+bx+c=0}}}
(-b/a)=sum of the roots
(c/a)=product of the roots<br>
let co-efficient of x^2 be 1
then we get,
(-b)=sum,(c)=product
-b=8,c=9
b=-8,c=9
substituting these values in our above equation,
{{{ax^2+bx+c=0}}}
{{{x^2-8x+9=0}}}
<p>
Hope this helps,
Prabhat