Question 131067
"A person's wage increased by a% to $250 per week. The wage prior to this increase in $ was: 
a) 250 - (a/100 x 250)
b) a/100 x 250
c) (100 + a)/100 x 250
d) 100/(100 + a) x 250
e) 250/a x 100 
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Let "x" be the person's wage prior to the increase.
EQUATION:
Person's wage after the increase = x + (a/100)x
250 = x + (a/100)x
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Solve for "x":
x[1+(a/100)] = 250
x[100+a]/100 = 250
x = 250*100/[100+a]
x = [100/(100+a)]*250
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Answer: "d"
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Cheers,
Stan H.