Question 131014

{{{(a - 1)/(1^2 - 4) + 1/( 1 - 2) = (a + 4)/( a + 2)}}}

{{{(a - 1)/( - 3) + 1/(-1) = (a + 4)/( a + 2)}}}

{{{-(a - 1)/3 - 1 = (a + 4)/( a + 2)}}}.....both sides multiply by {{{3(a+2) }}}

{{{-(a - 1)cross(3)(a+2)/cross(3) - 1*3(a+2) = 3cross((a+2))(a + 4)/cross(( a + 2))}}}

{{{-(a - 1)(a+2) -3(a+2) = 3(a + 4)}}}

{{{(-a + 1)(a+2) -3a+6 = 3a + 12}}}

{{{-a^2-2a+a+2 -3a+6 = 3a + 12}}}

{{{-a^2-4a+8 = 3a + 12}}}

{{{-a^2-4a+8-3a- 12=0}}}

{{{-a^2-7a-4=0}}}