Question 131054
Let x=measure of angle A


If we draw the triangle, it would look something like this:

{{{drawing(500,500,-0.5,2,-0.5,3.2,

line(0,0,0,3),
line(0,3,2,0),
line(2,0,0,0),
locate(-0.2,1.5,2.5),
locate(1,-0.2,4.5),
locate(-.1,3,A),
locate(0,0,B),
locate(2,0,C),
locate(.01,2.85,X)

)}}}


To find angle A, we can use trigonometry to do so. We can use the tangent function to find the measure of angle A


Remember *[Tex \LARGE \tan\left(x\right)=\frac{\textrm{opposite}}{\textrm{adjacent}}=\frac{4.5}{2.5}=1.8]



So


*[Tex \LARGE \tan\left(x\right)=1.8]



*[Tex \LARGE x=tan^{-1}\left(1.8\right)] Now take the inverse tangent of both sides



*[Tex \LARGE x=60.95] Take the inverse tangent of 1.8 to get 60.95




So the measure of angle A is about 60.95 degrees