Question 19791
total posts:560
one team set up 3/4 of the other team
let the faster team set up x number of posts
then the other team setup (3/4)of x
we know that both of these add up to 560
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so we get,
x+(3/4)x=560
{{{(1+(3/4))x=560}}}
((4+3)/4)x=560
(7/4)x=560
x=(560*4)/7
x=2240/7
x=320
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so the faster team set up 320 posts
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Hope this helps,
-Prabhat