Question 130475
9(^2x-1)= (81^(x+1)(27^-x)
(3^2)^2x-1=(3^4)^x+1(3^3)^-x  Change 9,81and 27 to bases of 3
3^4x-2=3^4x+4(3^-3x)   power to power: multiply exponents
 3^4x-2=3^x+4           multiply like bases:add exponents
4x-2=x+4                equate exponents
3x=6
x=2