Question 130908
Determine graphically the vertices of the triangle, the equation of whose sides are given as y=x;y=0; 2x+3y=10.  Interpret the result.
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{{{graph(400,300,-10,10,-10,10,x,0,(-2/3)x+(10/3))}}}
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Vertices:
Intersection of y=x and 2x+3y=10
Substitute to get:
2y+3y=10
5y=10
y=2
Therefore x=2
Intersection point is (2,2)
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x-intercept of 2x+3y=10
Let y=0, then x = 5
Intersection point is (5,0)
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Intersection of y=0 and y=x
(0,0)
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Cheers,
Stan H.