<PRE><B>Question 130894</B>
solution-
   Given the Perimeter of a triangle is 73
   Let the first side be x
           second side = 2x
           third side = x+5
     PERIMETER OF A TRIANGLE = SUM OF ALL SIDES
             73=X+2X+X+5
             73=4X+5
             73-5=4X+5-5
             68=4X
             68/4=4X/4
              17=X
    THIS IMPLISE THAT FIRST SIDE IS X = 17
                      SECOND SIDE IS 2X= 2*17=34
                      THIRD SIDE IS X+5=17+5=22

    FOR MORE HELP VISIT : WWW.TAKEATUITION.COM 
 </PRE>