Question 130718
by rules of logs __ {{{(x-5)/(x+4)=(x-1)/(x+2)}}}


"cross" multiplying __ x^2-3x-10=x^2+3x-4 __ subtracting x^2 __ -3x-10=3x-4


adding 3x+4 __ -6=6x


substituting the value of x into the original equation results in two of the ln arguments being negative
__ since logs are not defined for negative quantities, there is no solution for this equation