Question 130717
log(5x+1)=log(2x+3)+log2

log(5x+1)-log(2x+3)=log2

property of Logarithms
{{{log( (x/y)) = log x - log y}}}

{{{log ((5x+1)/(2x+3))}}} = {{{log 2}}}

Take antilog of both sides to cancel the log

{{{((5x+1)/ (2x+3)) = 2}}}
(5x+1) = 2(2x+3) 
5x + 1 = 4x +6
5x-4x = 6-1
x = 5