Question 130636
Solve for {{{x^2-4x+10 = 0}}} x using the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}} Make the appropriate substitutions of a = 1, b = -4, and c = 10.
{{{x = (-(-4)+-sqrt((-4)^2-4(1)(10)))/2(1)}}}
{{{x = (4+-sqrt(16-40))/2}}}
{{{x = (4+-sqrt(-24))/2}}}
{{{x = (4+-sqrt(-4*6))/2}}}
{{{x = 4/2+2*sqrt(-6)/2}}} or {{{x = 4/2 - 2*sqrt(-6)/2}}} Simplify.
{{{x = 2+sqrt(6)i}}} or {{{x = 2-sqrt(6)i}}}