Question 130654
(27)^(x-2)=(9^1/3)^x
3^(3x-6) = 3^(2x/3)
The logs(exponents) must be equal:
3x-6 = (2/3)x
9x-18 = 2x
7x = 18
x = 18/7
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You are correct.
Cheers,
Stan H.