Question 130649
Find the dimensions of a rectangular field that has a perimeter of 724m and an area of 32400m^2.
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Perimeter = 2(length + width)
724 = 2(length + width)
length + width = 362
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length * width = 32400
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EQUATIONS:
l = 362-w
Substitute to solve for width:
(362 -w)w = 32400
-w^2+362w-32400
w^2-362w+32400 = 0
w = [362 +- sqrt(1444)]/2
w = [362 +- 38]/2
w = 200 (width)
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Solve for length:
l + 200 = 362
l = 162 (length)
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Cheers,
Stan H.