Question 130639
{{{f(x)=b^x}}} Start with the given function



{{{1/64=b^(-2)}}} Plug in x=-2 and {{{f(-2)=1/64}}}



{{{1/64=1/b^2}}} Rewrite {{{b^(-2)}}} as {{{1/b^2}}}



{{{b^2=64}}} Cross multiply



{{{b=sqrt(64)}}} Take the square root of both sides



{{{b=8}}} Take the square root of 64 to get 8 


So the function is {{{f(x)=8^x}}}