Question 130537

12/sqrt(5x+6) = sqrt(2x+5)
then
12=sqrt(5x+6)sqrt(2x+5)
then
12^2=(sqrt(5x+6)sqrt(2x+5))^2
then
144=(5x+6)(2x+5)
then
10x^2+37x+30=144
then
10x^2+37x-114=0
then
{{{x = (-37 +- sqrt( 37^2-4*10*(-114) ))/(2*10) }}} 
then
{{{x = (-37 +- sqrt( 5929 ))/20 }}} 
then
{{{x = (-37 +- 77)/20 }}} 
then x=-5.5 or x=2
but in the original equation x=-5.5 produces a sqrt of a negative number
so the only solution is

x=2