Question 130506

{{{(9u^2 - 4)/(3u^2  + 7u - 6)}}} Start with the given expression


{{{((3u+2)(3u-2))/(3u^2  + 7u - 6)}}}   Factor {{{9u^2 - 4}}} to get {{{(3u+2)(3u-2)}}} 


{{{((3u+2)(3u-2))/((u+3)(3u-2))}}}   Factor {{{3u^2  + 7u - 6}}} to get {{{(u+3)(3u-2)}}} 




{{{(3u+2)cross((3u-2))/(u+3)cross((3u-2))}}} Cancel like terms



{{{(3u+2)/(u+3)}}} Simplify



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Answer:


So {{{(9u^2 - 4)/(3u^2  + 7u - 6)}}} simplifies to {{{(3u+2)/(u+3)}}}. In other words {{{(9u^2 - 4)/(3u^2  + 7u - 6)=(3u+2)/(u+3)}}}