Question 130390
here is a "rule of thumb" for mixture problems
__ the average of 80% and 30% is 55% __ this is what you get mixing them in equal parts
__ since the mixture is supposed to be 62%, it must be more than half of the 80%
__ so the amount of 80% is more than 100L


let x="amount of 80%", so 200-x="amount of 30%"


(80%)(x)+(30%)(200-x)=(62%)(200) __ .8x+60-.3x=124 __ .5x=64