Question 19709
I actully do not know how do you want this equation to be. So I will do it in quadratic function, if it turns out to be that you had to do it in a completing the square e-mail me back.

 Simplify the equation we get: {{{x^2+8x-32=0}}}
a=1,b=8,c=-32
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-(8) +- sqrt( (8)^2-4*(1)*(-32) ))/(2*(1)) }}} 
{{{x = (-8 +- sqrt( 64+128 ))/(2*1) }}} 
{{{x = (-8 +- sqrt( 192 ))/(2) }}} 
{{{x = -4 +- sqrt( 192 )}}}