Question 130378


Let's denote the first point (5,3) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=5] and *[Tex \LARGE y_{1}=3]


Now let's denote the second point (-2,-3) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=-2] and *[Tex \Large y_{2}=-3]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(-3-3)/(-2-5)}}} Plug in {{{y[2]=-3}}},{{{y[1]=3}}},{{{x[2]=-2}}},{{{x[1]=5}}}



{{{m=-6/-7}}} Subtract the terms in the numerator {{{-3-3}}} to get {{{-6}}}.  Subtract the terms in the denominator {{{-2-5}}} to get {{{-7}}}

  

{{{m=6/7}}} Reduce


  

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Answer:


So the slope of the line through the points (5,3) and (-2,-3) is {{{m=6/7}}}