Question 130364

{{{(3x-5)(2x+7)}}} Start with the given expression



Now let's FOIL the expression




Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(3x)-5)(highlight(2x)+7)}}} Multiply the First terms:{{{(3x)*(2x)=6x^2}}}



{{{(highlight(3x)-5)(2x+highlight(7))}}} Multiply the Outer terms:{{{(3x)*(7)=21x}}}



{{{(3x+highlight(-5))(highlight(2x)+7)}}} Multiply the Inner terms:{{{(-5)*(2x)=-10x}}}



{{{(3x+highlight(-5))(2x+highlight(7))}}} Multiply the Last terms:{{{(-5)*(7)=-35}}}



{{{6x^2+21x-10x-35}}} Now collect every term to make a single expression




{{{6x^2+11x-35}}} Now combine like terms



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Answer:

So {{{(3x-5)(2x+7)}}} foils and simplifies to  {{{6x^2+11x-35}}}


In other words, {{{(3x-5)(2x+7)=6x^2+11x-35}}}