Question 130374

{{{(1/6)v+1=(1/4)v-1}}} Start with the given equation




{{{(12)((1/cross(6))v+1)=(12)((1/cross(4))v-1)}}} Multiply both sides by the LCM of 12. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{2v+12=3v-12}}} Distribute and multiply the LCM to each side




{{{2v=3v-12-12}}}Subtract 12 from both sides



{{{2v-3v=-12-12}}} Subtract 3v from both sides



{{{-v=-12-12}}} Combine like terms on the left side



{{{-v=-24}}} Combine like terms on the right side



{{{v=(-24)/(-1)}}} Divide both sides by -1 to isolate v




{{{v=24}}} Divide


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Answer:

So our answer is {{{v=24}}}