Question 130278
Simplify:
{{{(12y-2xy-2x^2y)/(6y-4xy-2x^2y)}}} First, factor a 2 from both the numerator and the denominator to ease the calculations a bit.
{{{2(6y-xy-x^2y)/2(3y-2xy-x^2y)}}} Cancel the 2's.
{{{(6y-xy-x^2y)/(3y-2xy-x^2y)}}} Now factor the trinomial in the numerator and the trinomial in the denominator.
{{{(2y-xy)(3+x)/(y-xy)(3+x)}}} Cancel the (3+x)'s
{{{(2y-xy)/(y-xy)}}} Now factor a y from the numerator and from the denominator.
{{{y(2-x)/y(1-x)}}} Cancel the y's.
{{{(2-x)/(1-x)}}} but this can also be written:
{{{(-(x-2))/(-(x-1))}}} or {{{(x-2)/(x-1)}}}