Question 130252
Find the limit, as x approaches zero, of:
{{{3x/(x^3-x)}}} First, factor an x from the denominator.
{{{3cross(x)/cross(x)(x^2-1)}}} Cancel the the indicated x's
{{{3/(x^2-1)}}} Now you can see that, as x approaches zero, the denominator gets closer and closer to -1.
So the limit is{{{3/(0-1)}}} or {{{-3}}}