Question 19627
let the side of one square be x,and the other have side y
<P>
area of first square:{{{x^2}}}
area of second square:{{{y^2}}}
<br>
acc to the question,
"The combined are of two squares is 26 square meters."
{{{x^2+y^2=26}}}
<P>
now look at the question,
"The sides of the larger square are five times as long as the sides of the smaller squarer."
so that means,
x=5y
<P>
substitute this value in the first equation:
{{{x^2+y^2=26}}}
{{{(5y)^2+y^2=26}}}
{{{25*y^2+y^2=26}}}
{{{26y^2=26}}}
{{{y^2=1}}}
y=1
<br>
x=5y=5(1)=5
<P>
x=5,y=1 (metres)<P>-Prabhat