<PRE><B>Question 130081</B>
Find two consecutive integers such that 4 times the larger exceeds 3 times the smaller by 23. Steps would be helpful.

1st integer = n   (smaller)
2nd integer = n+1 (larger)

4 times the larger exceeds 3 times the smaller by 23
then 4(n+1)=3n+23
then 4n+4=3n+23 then 4n-3n=23-4 then n=19 and n+1=20

R: 19 and 20
</PRE>