Question 19622
very simple topic really.


The critical thing you need to remember is y=mx+c. Any straight line will/can be written like this, where m is the gradient and c is the y-intercept.


So, we have the line y = (5/2)x + 6... it is written in standard form, so its gradient is 5/2. 


The line we are asked for, is parallel to this one. Parallel means the same gradient, so our line has m=5/2, so we have...


y = (5/2)x + c


Now we need to know c. Well to do that, we need to know x and y, ie a point on the line...which surprise surprise, we do, namely (2,1). So, putting these into the equation, we get


1 = (5/2)(2) + c
--> 1 = 5 + c
--> -4 = c


so, that is it, our equation is y = (5/2)x - 4, which we may write without fractions as 2y = 5x - 8.


jon.