Question 129487
difference of squares __ x^6-y^6=(x^3+y^3)(x^3-y^3)


difference of cubes __ x^3-y^3=(x-y)(x^2+xy+y^2)


sum of cubes __ x^3+y^3=(x+y)(x^2-xy+y^2)


x^6-y^6=(x-y)(x^2+xy+y^2)(x+y)(x^2-xy+y^2)