Question 129813
{{{f(x) = -x^2 + 3x - 1}}}
The {{{x}}} value at the vertex is {{{-(b/2a)}}}
when equation is in the form {{{y = ax^2 + bx + c}}}
{{{a = -1}}}
{{{b = 3}}}
{{{-(b/2a) = -(3/(2*(-1)))}}}
{{{-(b/2a) = 3/2}}}
{{{f(x) = -x^2 + 3x - 1}}}
{{{f(3/2) = -(3/2)^2 + 3(3/2) - 1}}}
{{{f(3/2) = -(9/4) + 18/4 - 4/4}}}
{{{f(3/2) = 5/4}}}
The vertex is at (3/2,5/4)
{{{ graph( 700, 700, -2, 5, -2, 3, -x^2 + 3x - 1) }}}