Question 129729


Let's denote the first point (-4,1) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=-4] and *[Tex \LARGE y_{1}=1]


Now let's denote the second point (3,8) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=3] and *[Tex \Large y_{2}=8]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(8-1)/(3--4)}}} Plug in {{{y[2]=8}}},{{{y[1]=1}}},{{{x[2]=3}}},{{{x[1]=-4}}}



{{{m=7/7}}} Subtract the terms in the numerator {{{8-1}}} to get {{{7}}}.  Subtract the terms in the denominator {{{3--4}}} to get {{{7}}}

  

{{{m=1}}} Reduce


  

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Answer:


So the slope of the line through the points (-4,1) and (3,8) is {{{m=1}}}