Question 129755
Let x represent the first number.
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The second number equals the first number diminished by 4. So the second number is x - 4.
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The third number is 4 times the first number. So the third number is 4x.
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The sum of the three numbers is 62. So we can write the equation:
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x + x - 4 + 4x = 62
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Combine the terms in x on the left side (x + x + 4x = 6x) and the equation becomes:
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6x - 4 = 62
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Get rid of the -4 on the left side by adding 4 to both sides and you have:
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6x = 66
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Solve for x by dividing both sides by 6 and you have:
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x = 66/6 = 11
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So the first number is 11. The second number is 11 minus 4 and that is 7. An the third number
is the first number (11) times 4 which is 44.
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The three numbers are 11, 7, and 44. If you add them up you will find that their total is 62.
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Hope this helps you to understand the problem.
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