Question 129697


First convert the standard equation {{{5x-3y=7}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 5, -3, 7, 2, 1]




Now let's find the equation of the line that is perpendicular to {{{y=(5/3)x-7/3}}} which goes through (8,-2)


*[invoke equation_parallel_or_perpendicular "perpendicular", "5/3", "-7/3", 8,-2]