Question 129432
Problem 1:
Harold Hacker recently read in a national golf magazine that the average weekend golfer carries a handicap of 15 strokes and the standard deviation is 4 strokes. Harold manages a local men’s church league and just tallied the end-of-season totals. The 64 players in Harold’s league finished the year with an average handicap of 14 strokes. 
a. Set up the null and alternative hypotheses to test if the average handicap in Harold’s league is not the same as the national average reported in the magazine.
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Ho: mu = 15
Ha: mu is not 15
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b. Test your hypothesis using  = 0.02.
t(14) = (14-15)/[4/sqrt(64)] = -1*8/14 = -4/7 = -0.5714..
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c. Find the p value. 
p-value = P(-10<t<-0.5714 with df = 63) = 0.2848...
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d. Based on Harold’s end-of-season data, what can you conclude?
The p-value is greater than 1% (half of 2% of this two-tailed test)
so we Fail to reject Ho.
Harold's results are statistically in keping with the published
national average.
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Cheers,
StanH.