Question 129607
Ok! Hello this is HyperBrain.

Let d<sub>1</sub> be the first dice and d<sub>2</sub> be the second dice.
<hr>
As we all know, a die has 6 numbers (1,2,3,4,5,6)
<img src="http://tbn0.google.com/images?q=tbn:nHM4AamhAfQNJM:http://www.thinkport.org/microsites/blog/images/Dice.jpg"></img>

So D<sub>1</sub> can produce 1,2,3,4,5, or a 6.
Same as for D<sub>2</sub>

So, here are the possible combinations

<img src="http://images.adrianvidal07.multiply.com/image/2/photos/1/400x400/1/Dice.jpg?et=q6GSzuo20RQpdlD44rSE%2Bg&nmid=84035691"></img>
Now, i will highlight the ones that have the sum of 9.
<img src="http://images.adrianvidal07.multiply.com/image/2/photos/2/400x400/1/Dice2.jpg?et=%2BhUEkmbAAj0U8MVToj95vw&nmid=84036499"></img>


Now, the formula! tandandan!

PRObability=(no. of highlighted cells)/(total no. of cells)
<p>        =4/36=1/9


Power up,
HyperBrain!