Question 129464

If the initial quantity {{{x}}}, then:


{{{(1/5)x + (3/8)x  = (2/5)x + 22m }}}…..multiply both sides by {{{5*8}}}

{{{5*8 (1/5)x + 5*8 (3/8)x  = 5*8 (2/5)x + 5*8*22m }}}

{{{cross(5)*8 (1/cross(5))x + 5*cross(8) (3/cross(8))x  = cross(5)*8 (2/cross(5))x + 5*8*22m }}}

{{{8x + 5 (3)x  = 8 (2)x + 5*8*22m }}}

{{{8x + 15x  = 16x + 880m }}}

{{{8x + 15x – 16x  =  880m }}}

{{{7x  =  880m }}}

{{{7x  =  125.7m }}}

{{{1/5(x)=125.7/5= 25.14m}}}
{{{3/8(x)= 3*125.7/8 =377.1/8= 47.125m}}}

{{{25.14m + 47.125m    =  (2/5) 125.7m  + 22 }}}
{{{72.265m =  50.28 + 22 }}}
{{{72.27m =  72.28}}}
{{{72 =72}}}